WBJEE · Chemistry · Practical Chemistry
When \(\mathrm{BaCl}_{2}\) is added to an aqueous salt solution, a white precipitate is obtained. The anion among \(\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}\) and \(\mathrm{SO}_{4}^{2-}\) that was present in the solution can be
- A \(\mathrm{CO}_{3}^{2-}\) but not any of the other two
- B \(S O_{3}^{2-}\) but not any of the other two
- C \(\mathrm{SO}_{4}^{2-}\) but not any of the other two
- D Any of them
Answer & Solution
Correct Answer
(D) Any of them
Step-by-step Solution
Detailed explanation
\(\because\) If \(\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}\) and \(\mathrm{SO}_{4}^{2-}\) are present alongwith \(\mathrm{BaCl}_{2}\), these can also show white precipitate (as precipitate of all these are also white ).
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