WBJEE · Chemistry · States of Matter
\(360 \mathrm{~cm}^3\) of a hydrocabon diffuses in 30 minutes, while under the same conditions \(360 \mathrm{~cm}^3\) of \(\mathrm{SO}_2\) gas diffuses in one hour. The molecular formula of the hydrocabon is
- A \(\mathrm{CH}_4\)
- B \(\mathrm{C}_2 \mathrm{H}_6\)
- C \(\mathrm{C}_2 \mathrm{H}_4\)
- D \(\mathrm{C}_2 \mathrm{H}_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{CH}_4\)
Step-by-step Solution
Detailed explanation
According to Graham's Law: (MW = Molecular Weight)…
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