WBJEE · Chemistry · Chemical Bonding and Molecular Structure
The structure of \(\mathrm{XeF}_{6}\) is experimentally determined to be distorted octahedron. Its structure according to VSEPR theory is
- A octahedron
- B trigonal bipyramid
- C pentagonal bipyramid
- D tetragonal bipyramid
Answer & Solution
Correct Answer
(C) pentagonal bipyramid
Step-by-step Solution
Detailed explanation
In \(\mathrm{XeF}_{6}\). Xe, the central atom \(\mathrm{F}\) contains, 8 valence electrons. Out of which 6 are utilised with fluorine in bonding (ie., it contains six bond pairs of electrons) while one pair remains as lone pair. Thus, the total pairs \(=6+1=7\) Hence, its shape…
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