WBJEE · Chemistry · Coordination Compounds
Nickel combines with a uninegative monodentate ligand \(\left(\mathrm{X}^{-}\right)\)to form a paramagnetic complex \(\left[\mathrm{NiX}_4\right]^{2-}\). The hybridisation involved and number of unpaired electrons present in the complex are respectively.
- A \(\mathrm{sp}^3\) two
- B \(\mathrm{dsp}^2\), zero
- C \(\mathrm{dsp}^2\), one
- D \(\mathrm{sp}^3\), one
Answer & Solution
Correct Answer
(A) \(\mathrm{sp}^3\) two
Step-by-step Solution
Detailed explanation
Hint : \(\mathrm{Ni}^{2+}\left(\mathrm{d}^8\right)\) it should be paramagnetic with 2 unpaired electrons
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