WBJEE · Maths · Properties of Triangles
The incentre of an equilateral triangle is (1,1) and the equation of ene side is \(3 x+4 y+3=0 .\) Then, the equation of the circumeircle of the triangle is
- A \(x^{2}+y^{2}-2 x-2 y-2=0\)
- B \(x^{2}+y^{2}-2 x-2 y-14=0\)
- C \(x^{2}+y^{2}-2 x-2 y+2=0\)
- D \(x^{2}+y^{2}-2 x-2 y+14=0\)
Answer & Solution
Correct Answer
(B) \(x^{2}+y^{2}-2 x-2 y-14=0\)
Step-by-step Solution
Detailed explanation
since, triangle is equilateral the refore incentre (1,1) lies on the centroid of the \(\Delta A B C\). \(\therefore G D=\) Length of perpendicular from the point \(G(1,1)\) to the line \(3 x+4 y+3=0\) \(A G=2 G D=4\) \(\therefore\) Equation of circumcircle with centre at (1,1)…
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