WBJEE · Chemistry · States of Matter
The compressibility factor for a van der Waal gas at high pressure is
- A \(1+\frac{\mathrm{RT}}{\mathrm{Pb}}\)
- B \(1+\frac{\mathrm{Pb}}{\mathrm{RT}}\)
- C \(1-\frac{\mathrm{Pb}}{\mathrm{RT}}\)
- D 1
Answer & Solution
Correct Answer
(B) \(1+\frac{\mathrm{Pb}}{\mathrm{RT}}\)
Step-by-step Solution
Detailed explanation
For 1 mol van der Waal's gas \(\left(P+\frac{a}{V^2}\right)(v-b)=R T\) At high pressure \(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2} \approx \mathrm{P}\)…
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