WBJEE · Chemistry · Some Basic Concepts of Chemistry
\(5 \mathrm{~m}\) of \(0.1 \mathrm{M} ~ \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) is mixed with \(10 \mathrm{ml}\) of \(0.02 \mathrm{M} ~ \mathrm{KI}\). The amount of \(\mathrm{Pbl}_{2}\) precipitated will be about
- A \(10^{-2} \mathrm{~mol}\)
- B \(10^{-4} \mathrm{~mol}\)
- C \(2 \times 10^{-4} \mathrm{~mol}\)
- D \(10^{-3} \mathrm{~mol}\)
Answer & Solution
Correct Answer
(B) \(10^{-4} \mathrm{~mol}\)
Step-by-step Solution
Detailed explanation
Hint: mole of \(\mathrm{Pbl}_{2} \quad \mathrm{PPt}=\frac{0.1}{1000}=1 \times 10^{-4}\)
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