TS EAMCET · Physics · Waves and Sound
Two strings \(\mathrm{A}\) and \(\mathrm{B}\) produce beat of frequency \(\Delta f_1>0\). The tension in string \(\mathrm{A}\) is slightly increased and the beat frequency is found to be \(\Delta f_2>0\). If the original frequency of \(\mathrm{A}\) is \(f_0\) and \(\Delta f_2 < \Delta f_1\), then the frequency of \(\mathrm{B}\) is
- A \(f_0+\Delta f_1\)
- B \(f_0+\Delta f_1-\Delta f_2\)
- C \(f_0-\Delta f_1\)
- D \(f_0+\frac{\left(\Delta f_1+\Delta f_2\right)}{2}\)
Answer & Solution
Correct Answer
(A) \(f_0+\Delta f_1\)
Step-by-step Solution
Detailed explanation
Frequency of string \(\mathrm{A}, \mathrm{f}_{\mathrm{A}}=\mathrm{f}_0\) Frequency of string \(B, f_B=f_2\) We know, beat frequency…
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