TS EAMCET · Physics · Motion In One Dimension
A car accelerates from rest with \(2 \mathrm{~m} / \mathrm{s}^2\) on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is \(100 \mathrm{~m}\) in 20 seconds. Then, the maximum velocity attained by the car is
- A \(10 \mathrm{~m} / \mathrm{s}\)
- B \(20 \mathrm{~m} / \mathrm{s}\)
- C \(15 \mathrm{~m} / \mathrm{s}\)
- D \(5 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Given, Acceleration of \(\operatorname{car}(\alpha)=2 \mathrm{~m} / \mathrm{s}^2\) Distance covered by car in 20 seconds \((s)=100 \mathrm{~m}\) We know that,…
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