TS EAMCET · Physics · Nuclear Physics
An alloy is composed of two radioactive materials \(A\) and \(B\) having equal weight. The half life of \(A\) and \(B\) are 10 yrs and \(20 \mathrm{yrs}\) respectively. After time \(t\), the alloy was found to consist of \(\left(\frac{1}{e}\right) \mathrm{kg}\) of \(A\) and \(1 \mathrm{~kg}\) of \(B\). . If the atomic weight of \(A\) and \(B\) are same, then the value of \(t\) is (Assume, \(\ln 2=0.7\) )
- A \(\left(\frac{200}{7}\right) \mathrm{yrs}\)
- B \(\left(\frac{10}{7}\right) \mathrm{yrs}\)
- C 7 yrs
- D 70 yrs
Answer & Solution
Correct Answer
(A) \(\left(\frac{200}{7}\right) \mathrm{yrs}\)
Step-by-step Solution
Detailed explanation
Given, initial amount of radioactive element, \(A=\) initial amount of radioactive element, \(B\) i.e., \(\left(N_0\right)_A=\left(N_0\right)_B\) half life of element \(A,\left(t_2 / 2\right)_A=10 \mathrm{Yr}\) and half life of element…
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