TS EAMCET · Physics · Magnetic Effects of Current
A coil having 2000 turns is wound tightly in the form of a spiral with inner and outer radii \(1 \mathrm{~cm}\) and \(3 \mathrm{~cm}\), respectively. When a current \(\frac{1}{\pi} \mathrm{mA}\) passes through the coil, then the magnetic field at the centre is calculated be \(K \ln 3 \times 10^{-6} \mathrm{~T}\). The value of \(K\) is
- A 20
- B 36
- C 15
- D 25
Answer & Solution
Correct Answer
(B) 36
Step-by-step Solution
Detailed explanation
Number of turns, \(N=2000\) Inner radius, \(r_1=1 \mathrm{~cm}\) Outer radius, \(r_2=3 \mathrm{~cm}\) Current, \(I=\frac{1}{\pi} \mathrm{mA}=\frac{10^{-3}}{\pi} \mathrm{A}\) Magnetic field at the centre of the coil, \(B=\frac{\mu_0 N I}{2 r}\)…
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