TS EAMCET · Physics · Electromagnetic Waves
If electromagnetic waves of power 600 W incident on a non-reflecting surface, then the total force acting on the surface is
- A \(12 \times 10^{-6} \mathrm{~N}\)
- B \(9 \times 10^{-9} \mathrm{~N}\)
- C \(6 \times 10^{-6} \mathrm{~N}\)
- D \(2 \times 10^{-6} \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(2 \times 10^{-6} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(F = \frac{P}{c}\) \(F = \frac{600}{3 \times 10^8}\) \(F = 2 \times 10^{-6} \mathrm{~N}\)
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