TS EAMCET · Physics · Thermodynamics
One mole of the ideal gas goes through the process \(p=p_0\left[1-\alpha\left(\frac{V}{V_0}\right)^3\right]\), where \(p\) and \(V\) are pressure and volume, \(p_0, V_0\) and \(\alpha\) are constants. If the maximum attainable temperature of the gas is \(\left(\frac{3}{4}\right) \frac{p_0 V_0}{R}\), then the value of \(\alpha\) is
- A 2
- B \(\frac{1}{2}\)
- C \(\frac{1}{4}\)
- D 4
Answer & Solution
Correct Answer
(C) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
For 1 mole of an ideal gas, \[ p=\frac{R T}{V} \] But, \[ p=p_0\left(1-\frac{\alpha V^3}{V_0^3}\right) \] (given) So, \[ \begin{gathered} \frac{R T}{V}=p_0-\frac{\alpha p_0}{V_0^3} V^3 \\ T=\frac{p_0 V}{R}-\frac{\alpha p_0 V^4}{V_0^3 R} \end{gathered} \] For maximum \(T\),…
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