TS EAMCET · Physics · Thermodynamics
Two moles of a gas is expanded to double its volume by two different processes. One is isobaric and the other is isothermal. If \(W_1\) and \(W_2\) are the works done, respectively then
- A \(W_2=\frac{W_1}{\log e^2}\)
- B \(W_2=W_1\)
- C \(W_2=W_1\) loge \(e^2\)
- D \(W_2=W_1 \log _e(2)\)
Answer & Solution
Correct Answer
(D) \(W_2=W_1 \log _e(2)\)
Step-by-step Solution
Detailed explanation
Given, In the first condition, work done \(=W_1\) In the second condition, work done \(=W_2\) Now, according to the question, In the first condition, or, \[ \begin{aligned} & W_1=p(2 V-V) \\ & W_1=p V \end{aligned} \] In the second condition,…
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