TS EAMCET · Physics · Nuclear Physics
The half lives of two radioactive materials \(A\) and \(B\) are respectively \(T\) and \(2 T\). If the ratio of the initial masses of the materials \(A\) and \(B\) is \(8: 1\), then the time after which the ratio of the masses of the materials \(A\) and \(B\) becomes \(4: 1\) is
- A \(2 T\)
- B \(4 T\)
- C \(T\)
- D \(8 T\)
Answer & Solution
Correct Answer
(A) \(2 T\)
Step-by-step Solution
Detailed explanation
From the law of radioactive decay. \(\mathrm{M}=\mathrm{M}_0\left(\frac{1}{2}\right)^{\frac{\mathrm{t}}{(\mathrm{~T} / 2)}}\) Here, \(\mathrm{M}_0=\) initial mass \(\mathrm{M}=\) mass left after time t \(\mathrm{T} / 2=\) half live.…
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