TS EAMCET · Physics · Motion In One Dimension
A ball is thrown vertically upwards with an initial velcoity \(u\) reaches maximum height in \(5 \mathrm{~s}\). The ratio of distance travelled by the ball in the 2 nd and 7 th second is (assume, \(g=10\) \(\mathrm{m} / \mathrm{s}^2\) )
- A \(8: 19\)
- B \(16: 29\)
- C \(16: 49\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
When ball is at maximum height, its velocity is zero. From first equation of motion, \(v=u-g t \Rightarrow 0=u-10 \times 5 \Rightarrow u=50 \mathrm{~m} / \mathrm{s}\) Distance travelled in \(n\)th second, \(s_n=u+\frac{a}{2}(2 n-1)\) Distance travelled in 2nd second is given as…
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