TS EAMCET · Physics · Atomic Physics
In a hypothetical Bohr hydrogen atom, if the mass of the electron is doubled then the energy of the electron in the first orbit is
- A \(-27.2 \mathrm{eV}\)
- B \(-13.6 \mathrm{eV}\)
- C \(-6.8 \mathrm{eV}\)
- D \(-3.4 \mathrm{eV}\)
Answer & Solution
Correct Answer
(A) \(-27.2 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
Mass of the electron, \(\mathrm{m}=2 \mathrm{~m}\) Energy of electron, \(E \propto \frac{\mathrm{m}}{\mathrm{n}^2}\) For first orbit, \(\mathrm{n}=1\) \(\begin{aligned} & E=\frac{2 \times(-13.6)}{1} \\ & =-27.2 \mathrm{ev} \end{aligned}\)
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