TS EAMCET · Physics · Current Electricity
The Wheatstone bridge shown in the diagram is balanced. If \(\mathrm{P}_3\) is the power dissipated by \(\mathrm{R}_3\) and \(\mathrm{P}_1\) is the power dissipated by \(R_1\), then the ratio \(\frac{\mathrm{P}_3}{\mathrm{P}_1}\) is
- A \(\frac{\mathrm{K}}{\mathrm{L}}\)
- B \(\frac{\mathrm{K}^2}{\mathrm{~L}}\)
- C \(\frac{\mathrm{L}}{\mathrm{K}^2}\)
- D \(\frac{\mathrm{L}}{\mathrm{K}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{K}}{\mathrm{L}}\)
Step-by-step Solution
Detailed explanation
From wheat stone bridge, we have \(\begin{aligned} & \frac{R_1}{R_3}=\frac{L}{K} \\ & P=I^2 R \\ & \frac{P_3}{P_1}=\frac{I^2 R_3}{I^2 R_1}=\frac{K}{L}\end{aligned}\)
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