TS EAMCET · Physics · Laws of Motion
A body of weight \(50 \mathrm{~N}\) is placed on a horizontal surface as shown in the figure. The minimum force required to move the body is \(28.28 \mathrm{~N}\). The frictional force and the normal reaction are respectively.
- A \(10 \mathrm{~N}, 15 \mathrm{~N}\)
- B \(20 \mathrm{~N}, 30 \mathrm{~N}\)
- C \(2 \mathrm{~N}, 3 \mathrm{~N}\)
- D \(5 \mathrm{~N}, 6 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(20 \mathrm{~N}, 30 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
From the free body diagram Frictional force, \(f=F \cos 45\) \[ \begin{aligned} & =28.28 \cos 45 \\ & =28.28 \times \frac{1}{\sqrt{2}}=20 \mathrm{~N} \end{aligned} \] Normal reaction, \(\mathrm{R}=50-\mathrm{F} \sin 45\)…
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