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TS EAMCET · Physics · Mathematics in Physics

A capacitor of capacitance \((4.0 \pm 0.2) \mu \mathrm{F}\) is charged to a potential of \((10.0 \pm 0.1) \mathrm{V}\). The charge on the capacitor is

  1. A \(2.5 \mu \mathrm{C} \pm 3 \%\)
  2. B \(2.5 \mu \mathrm{C} \pm 6 \%\)
  3. C \(40 \mu \mathrm{C} \pm 3 \%\)
  4. D \(40 \mu \mathrm{C} \pm 6 \%\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(40 \mu \mathrm{C} \pm 6 \%\)

Step-by-step Solution

Detailed explanation

\(\mathrm{C}=(4.0 \pm 0.2) \mu \mathrm{F}, \mathrm{V}=(10.0 \pm 0.1) \mathrm{V}\) The charge on capacitor is \(Q=C V=4 \times 10=40 \mu C\) Also,…
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