TS EAMCET · Physics · Oscillations
The magnitude of maximum acceleration is \(\pi\) times that of maximum velocity of a simple harmonic oscillator. The time period of the oscillator in seconds is
- A \(4\)
- B \(2\)
- C \(1\)
- D \(0.5\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Maximum acceleration \(=\) Maximum velocity \(\times \pi\) ie, \(\omega^2 A=\pi \omega A\) where \(A\) is amplitude and \(\omega\) is angular velocity.…
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