TS EAMCET · Physics · Wave Optics
In Young's double slit experiment, intensity of light at a point on the screen where the path difference becomes \(\lambda\) is \(I\). The intensity at a point on the screen where the path difference becomes \(\frac{\lambda}{3}\) is,
- A \(\frac{I}{4}\)
- B \(\frac{I}{3}\)
- C \(\frac{2 I}{3}\)
- D \(3 I\)
Answer & Solution
Correct Answer
(A) \(\frac{I}{4}\)
Step-by-step Solution
Detailed explanation
In YDSE, \(\mathrm{I}_1=\mathrm{I}, \Delta \mathrm{x}_1=\lambda, \Delta \mathrm{x}_2=\frac{\lambda}{3}\)…
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