TS EAMCET · Physics · Oscillations
A simple pendulwm of length \(1 \mathrm{~m}\) is freely suspended from the ceiling of an elevator. The time period of small oscillations as the elevator moves up with an acceleration of \(2 \mathrm{~m} / \mathrm{s}^2\) is (use \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(\frac{\pi}{\sqrt{5}} \mathrm{~s}\)
- B \(\sqrt{\frac{2}{5}} \pi s\)
- C \(\frac{\pi}{\sqrt{2}} \mathrm{~s}\)
- D \(\frac{\pi}{\sqrt{3}} \mathrm{~s}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{\sqrt{3}} \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given, Length of simple pendulum \((L)=1 \mathrm{~m}\) Acceleration \((a)=2 \mathrm{~m} / \mathrm{s}^2\) Gravitation acceleration \((g)=10 \mathrm{~m} / \mathrm{s}^2\) We know that,…
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