TS EAMCET · Physics · Electromagnetic Induction
The magnetic field of an electromagneticwave obeys the relation in a certain region is \(B=10^{12} \sin \left(5 \times 10^6 t\right) \mathrm{T}\), where \(t\) is the time. Then, the induced emf, in a 300 tums in coil of area \(20 \mathrm{~cm}^2\) oriented perpendicular to the field is
- A \(-2 \times 10^{-5} \cos \left(5 \times 10^6 t\right) \mathrm{V}\)
- B \(-3 \times 10^{-6} \cos \left(5 \times 10^6 t\right) \mathrm{V}\)
- C \(-2.5 \times 10^{-6} \cos \left(5 \times 10^6 t\right) \mathrm{V}\)
- D \(-3.3 \times 10^{-6} \cos \left(5 \times 10^6 t\right)\)
Answer & Solution
Correct Answer
(B) \(-3 \times 10^{-6} \cos \left(5 \times 10^6 t\right) \mathrm{V}\)
Step-by-step Solution
Detailed explanation
Given, \(B=10^{-12} \sin \left(5 \times 10^6 t\right) \mathrm{T}, N=300\) turns and area, \(A=20 \mathrm{~cm}^2=20 \times 10^{-4} \mathrm{~m}^2\) Hence, the emf induced…
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