TS EAMCET · Physics · Mechanical Properties of Fluids
The work done in breaking a drop of liquid of radius \(R\) (Surface tension \(T\) ) into 64 equal drops is
- A \(4 \pi R^2 T\)
- B \(\frac{\pi R^2 T}{64}\)
- C \(\frac{12 \pi T}{R^2}\)
- D \(12 \pi R^2 T\)
Answer & Solution
Correct Answer
(D) \(12 \pi R^2 T\)
Step-by-step Solution
Detailed explanation
Radius of big drop \(=R\) Number of small drops, \(n=64\) Let radius of small drop \(=r\) In the process of breaking the drop, the volume of liquid drops remains constant. \[ V_i=V_f \]…
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