TS EAMCET · Physics · Work Power Energy
A motor of power \(P_0\) is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe \(n\) times, the power of the motor is increased to \(P_1\). The ratio of \(P_1\) to \(P_0\) is
- A \(n: 1\)
- B \(n^2: 1\)
- C \(n^3: 1\)
- D \(n^4: 1\)
Answer & Solution
Correct Answer
(A) \(n: 1\)
Step-by-step Solution
Detailed explanation
Power of motor initially \(=P_0\) Let, rate of flow of motor \(=(x)\) \(\text { Since, power, } \begin{aligned} P_0 & =\frac{\text { work }}{\text { time }}=\frac{m g y}{t} \\ & =m g\left(\frac{y}{t}\right), \\ \frac{y}{t} & =x=\text { rate of flow of water } \end{aligned}\) If…
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