TS EAMCET · Physics · Mechanical Properties of Solids
The work to be done to produce a strain of \(10^{-3}\) in a steel wire of mass 2.96 kg and density \(7.4 \mathrm{~g} \mathrm{~cm}^{-3}\) is
(Young's modulus of steel \(=2 \times 10^{11} \mathrm{Nm}^{-2}\) )
- A 0.04 kJ
- B 0.04 J
- C 100 kJ
- D 400 J
Answer & Solution
Correct Answer
(A) 0.04 kJ
Step-by-step Solution
Detailed explanation
\(\rho = 7.4 \mathrm{~g} \mathrm{~cm}^{-3} = 7.4 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}\) \(V = \frac{m}{\rho} = \frac{2.96 \mathrm{~kg}}{7.4 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}} = 4 \times 10^{-4} \mathrm{~m}^3\)…
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