TS EAMCET · Physics · Thermal Properties of Matter
The cold junction of a thermocouple is at \(0^{\circ} \mathrm{C}\). The thermo e.m.f produced in the thermocouple is given by an equation \(E=16 T-0.04 T^2\), where \(T\) is the temperature of the hot junction. The temperature of inversion and neutral temperature of the thermocouple are
- A \(200^{\circ} \mathrm{C} ; 400^{\circ} \mathrm{C}\)
- B \(400^{\circ} \mathrm{C} ; 200^{\circ} \mathrm{C}\)
- C \(200^{\circ} \mathrm{C} ; 300^{\circ} \mathrm{C}\)
- D \(300^{\circ} \mathrm{C} ; 200^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(400^{\circ} \mathrm{C} ; 200^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Thermo emf \(E=16 T-0.04 T^2\) At inversion temperature \(\left(T i\right), E=0\) \[ \therefore \quad \begin{aligned} 0 & =16 T_i-0.04 T_i^2 \\ 16 T i & =0.04 T_i^2 \\ T i & =\frac{16}{0.04}=400^{\circ} \mathrm{C} \end{aligned} \] Neutral temperature \(T_n=\frac{T i+T}{2}\)…
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