TS EAMCET · Physics · Magnetic Effects of Current
A steady current flows in a long wire. It is bent into a circular loop of one turn and the magnetic field at the centre of the coil is \(B\). If the same wire is bent into a circular loop of \(n\) turns, the magnetic field at the centre of the coil is
- A \(\frac{B}{n}\)
- B \(n B\)
- C \(n B^2\)
- D \(n^2 B\)
Answer & Solution
Correct Answer
(D) \(n^2 B\)
Step-by-step Solution
Detailed explanation
The magnetic field a circular coil (for \(n\) number of loops) \[ \begin{gathered} B=\frac{\mu_0 n i}{2 r} \\ n_1=1, n_2=2 \\ 2 \pi r_1=n \times 2 \pi r_2 \end{gathered} \] When, So…
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