TS EAMCET · Physics · Electromagnetic Induction
The thermo emf of a thermocouple is given by, \(E=a T+b T^2\), where \(\frac{a}{b}=-200^{\circ} \mathrm{C}\). If the cold function is kept at \(30^{\circ} \mathrm{C}\), then the inversion temperature is ( \(\varepsilon\) in volt, \(T\) in centigrade)
- A \(103 \mathrm{~K}\)
- B \(143 \mathrm{~K}\)
- C \(333 \mathrm{~K}\)
- D \(443 \mathrm{~K}\)
Answer & Solution
Correct Answer
(D) \(443 \mathrm{~K}\)
Step-by-step Solution
Detailed explanation
At temperature of inversion \(E=0\) \(\because \quad E=a T+b T^2\) \(\therefore \quad 0=a T+b T^2\) or \(\quad T=-\frac{a}{b}=200^{\circ} \mathrm{C}\) Because the cold function is kept at \(30^{\circ} \mathrm{C}\), then the inversion temperature…
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