TS EAMCET · Physics · Electromagnetic Induction
A wire loop of area \(0.2 \mathrm{~m}^2\) has a resistance of \(20 \Omega\). A magnetic field pointing normal to the loop has a magnitude of \(0.25 \mathrm{~T}\) and is reduced to zero at a uniform rate in \(10^{-4} \mathrm{sec}\). What is induced emf and resulting current?
- A \(50 \mathrm{~V}, 2.5 \mathrm{~A}\)
- B \(500 \mathrm{~V}, 25 \mathrm{~A}\)
- C \(250 \mathrm{~V}, 12.5 \mathrm{~A}\)
- D \(500 \mathrm{~V}, 2.5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(500 \mathrm{~V}, 25 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Induced emf is given by \[ \begin{aligned} & |\varepsilon|=\left|-\frac{\mathrm{dt}}{\mathrm{dt}}\right|=\left|-\frac{\mathrm{dB} \cdot \mathrm{A}}{\mathrm{dt}}\right| \\ & =\frac{0.25 \times 0.2}{10^{-4}}=500 \mathrm{~V} \end{aligned} \] Current, \(I=\frac{V}{R}\)…
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