TS EAMCET · Physics · Center of Mass Momentum and Collision
Two blocks of masses \(2 \mathrm{~kg}\) and \(1 \mathrm{~kg}\) are tied to the ends of a string which passes over a light frictionless pulley. The blocks are held at rest at the same horizontal level and then released suddenly. The distance traversed by their centre of mass in 2 seconds is (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(1.42 \mathrm{~m}\)
- B \(2.22 \mathrm{~m}\)
- C \(3.12 \mathrm{~m}\)
- D \(3.33 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(2.22 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The mass of two blocks are \(\mathrm{m}_1=2 \mathrm{~kg}\) and \(\mathrm{m}_2=1 \mathrm{~kg}\). The acceleration of masses is given as…
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