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TS EAMCET · Physics · Nuclear Physics

The de-Broglie wavelength of an electron having kinetic energy 100 eV is,
[Use h=4.14×10-15 eVs, mass of electron =0.5×106c2eV, 1pm=10-12 m]

  1. A 150.1pm
  2. B 124.2pm
  3. C 115.5pm
  4. D 120.8pm
Verified Solution

Answer & Solution

Correct Answer

(B) 124.2pm

Step-by-step Solution

Detailed explanation

Apply the de-Broglie wave equation, λ=hp to solve for the wavelength of the moving electron. Recall the proper formula of wavelength in terms of kinetic energy, λ=h2K.E.m, given, K.E.=100 eV=100×1.6×10-19 J, it means,…
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