TS EAMCET · Physics · Laws of Motion
In the pulley system shown in the figure, the mass of \(A\) is half of that of \(\operatorname{rod} B\). The rod length is \(500 \mathrm{~cm}\). The mass of pulleys and the threads may be neglected. The mass \(A\) is set at the same level as the lower end of the rod and then released. After releasing the mass \(A\), it would reach the top end of the rod \(B\) in time (Assume, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )

- A \(2.0 \mathrm{~s}\)
- B \(1.0 \mathrm{~s}\)
- C \(3.0 \mathrm{~s}\)
- D \(4.0 \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(1.0 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
\[ \text { According to the question, } \] Given, mass of body \(A\), is half of mass of \(\operatorname{rod} B\). i.e., \[ m_A=\frac{m_B}{2} \Rightarrow m_B=2 m_A \] and length of \(\operatorname{rod}=500 \mathrm{~cm}=5 \mathrm{~m}\) Since, \(\operatorname{rod} B\) and body…
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