TS EAMCET · Physics · Electrostatics
A hollow spherical shell of radius \(r\) has a uniform charge density \(\sigma\). It is kept in a cube of edge \(3 r\) such that the centres of the cube and the shell coincide. Then the electric flux coming out of one face of a cube is ( \(\varepsilon_0\) - permittivity of free space)
- A \(\frac{\pi \mathrm{r}^2 \sigma}{\varepsilon_0}\)
- B \(\frac{5 \varepsilon_0}{2 \pi r^2 \sigma}\)
- C \(\frac{\pi \mathrm{r}^2 \sigma}{6 \varepsilon_0}\)
- D \(\frac{2 \pi r^2 \sigma}{3 \varepsilon_0}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 \pi r^2 \sigma}{3 \varepsilon_0}\)
Step-by-step Solution
Detailed explanation
Charge on the hollow sphere, \(q=\sigma \times 4 \pi r^2\) According to Gauss's law, The flux through a single face of the cube,…
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