TS EAMCET · Physics · Motion In Two Dimensions
A player can throw a ball to a maximum horizontal distance of \(80 \mathrm{~m}\). If he throws the ball vertically with the same velocity, then the maximum height reached by the ball is
- A \(160 \mathrm{~m}\)
- B \(60 \mathrm{~m}\)
- C \(20 \mathrm{~m}\)
- D \(40 \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(40 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The maximum horizontal distances is given by \[ \begin{aligned} & \mathrm{H}_{\max }=\frac{\mathrm{u}^2}{\mathrm{~g}} \sin 90^{\circ} \Rightarrow 80=\frac{\mathrm{u}^2}{\mathrm{~g}} \\ & \mathrm{u}^2=80 \mathrm{~g} \end{aligned} \] The ball will achieve the maximum height when…
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