TS EAMCET · Physics · Nuclear Physics
In uranium radioactive series, initial nucleus \({ }^{238} \mathrm{U}_{92}\) decays to final nucleus \({ }^{206} \mathrm{U}_{82}\). In this process, the number of \(\alpha\)-particles and \(\beta\)-particles emitted are
- A 8 and 3
- B 16 and 6
- C 16 and 3
- D 8 and 6
Answer & Solution
Correct Answer
(D) 8 and 6
Step-by-step Solution
Detailed explanation
In decay, \({ }_{92}^{238} \mathrm{U} \longrightarrow{ }_{82}^{206} \mathrm{U}\) Mass number reduces by \(\Delta A=32=4 \times 8\) and proton number is reduces by \(\Delta Z=10=2 \times 8-6\) So, \(8 \alpha\)-particles and \(6 \beta^{-}\)-particles must be emitted.
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