TS EAMCET · Physics · Alternating Current
A resistor of resistance of \(100 \Omega\) is connected to an AC source \(\varepsilon=10 \sin \left(250 \pi \mathrm{s}^{-1}\right) \mathrm{t}\). The energy dissipated as heat during \(\mathrm{t}=0\) to \(\mathrm{t}=1 \mathrm{~ms}\) is approximately.
- A \(\frac{0.57}{\pi} \mathrm{mJ}\)
- B \(\frac{1.141}{\pi} \mathrm{mJ}\)
- C \(1 \mathrm{~mJ}\)
- D \(0.5 \mathrm{~mJ}\)
Answer & Solution
Correct Answer
(A) \(\frac{0.57}{\pi} \mathrm{mJ}\)
Step-by-step Solution
Detailed explanation
Given that \(\varepsilon=10 \sin \left(250 \pi \mathrm{s}^{-}\right) \mathrm{t}\) Compair with \(\varepsilon=\varepsilon_0 \sin (\omega \mathrm{t})\) \(\omega=250 \pi \mathrm{Rad} / \mathrm{s}\) The energy dissipated as…
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