TS EAMCET · Physics · Magnetic Effects of Current
The magnetic field due to a current carrying circular coil on its axis at a distance of \(\sqrt{2} \mathrm{~d}\) from the centre of the coil is B. If d is the diameter of the coil, then the magnetic field at the centre of the coil is
- A 18 B
- B 27 B
- C 3B
- D 9B
Answer & Solution
Correct Answer
(B) 27 B
Step-by-step Solution
Detailed explanation
\(R = d/2\) \(x = \sqrt{2} d = 2\sqrt{2} R\) \(B_{axial} = B_{center} \frac{R^3}{(R^2 + x^2)^{3/2}}\) \(B = B_{center} \frac{R^3}{(R^2 + (2\sqrt{2} R)^2)^{3/2}}\) \(B = B_{center} \frac{R^3}{(R^2 + 8R^2)^{3/2}}\) \(B = B_{center} \frac{R^3}{(9R^2)^{3/2}}\)…
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