TS EAMCET · Physics · Center of Mass Momentum and Collision
A body mass of \(1 \mathrm{~kg}\), initially at rest explodes and breaks into three parts. The masses of the parts are in the ratio \(1: 1: 3\). The two pieces of equal mass fly off perpendicular to each other with a speed of \(30 \mathrm{~m} / \mathrm{s}\) each. The velocity of the heavier part in \(\mathrm{m} / \mathrm{s}\) is
- A \(10 \sqrt{2}\)
- B 6
- C 3
- D \(6 \sqrt{2}\)
Answer & Solution
Correct Answer
(A) \(10 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Initial momentum before explosion is zero. Final momentum after explosion. \( \sqrt{2} \frac{m}{4} \times 30-\frac{3 m}{4} v^{\prime} \) From conservation of momentum Initial momentum \(=\) Final momentum…
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