TS EAMCET · Physics · Thermodynamics
A Carnot engine whose efficiency is \(40 \%\), receives heat at \(500 \mathrm{~K}\). If the efficiency is to be \(50 \%\), the source temperature for the same exhaust temperature is
- A \(900 \mathrm{~K}\)
- B \(600 \mathrm{~K}\)
- C \(700 \mathrm{~K}\)
- D \(800 \mathrm{~K}\)
Answer & Solution
Correct Answer
(B) \(600 \mathrm{~K}\)
Step-by-step Solution
Detailed explanation
We know that, efficiency of a Carnot engine is given by \(\eta=\left(1-\frac{T_2}{T_1}\right)\) Given, \(\eta_1=0.4\) and \(T_1=500 \mathrm{~K}\) (temperature of source) So, \(0.4=1-\frac{T_2}{500} \Rightarrow \frac{T_2}{500}=1-0.4=0.6\)…
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