TS EAMCET · Physics · Electrostatics
Along the \(x\)-axis, three charges \(\frac{q}{2},-q\) and \(\frac{q}{2}\) are placed at \(x=0, x=a\) and \(x=2 a\) respectively. The resultant electric potential at a point \(P\) located at a distance \(r\) from the charge \(-q(a < r)\) is \(\left(\varepsilon_0\right.\) is the permittivity of free space)
- A \(\frac{q a}{4 \pi \varepsilon_0 r^2}\)
- B \(\frac{q a^2}{4 \pi \varepsilon_0 r^3}\)
- C \(\frac{q\left(\frac{a^2}{4}\right)}{4 \pi \varepsilon_0 r^3}\)
- D \(\frac{q}{4 \pi \varepsilon_0 r}\)
Answer & Solution
Correct Answer
(B) \(\frac{q a^2}{4 \pi \varepsilon_0 r^3}\)
Step-by-step Solution
Detailed explanation
As \(r \gg a\), so \(r>2 a\) So, potential at point \(P\)…
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