TS EAMCET · Physics · Magnetic Properties of Matter
Two small magnets have their masses and lengths in the ratio 1:2. The maximum torques experienced by them in a uniform magnetic field are the same. For small oscillations, the ratio of their time periods is
- A \(\frac{1}{2 \sqrt{2}}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{2}\)
- D \(2 \sqrt{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
Let the mass of the first magnet \(=m\) \(\therefore\) Mass of second magnet \(=2 \mathrm{~m}\) The time-period of oscillation of the magnet \(T=2 \pi \sqrt{\frac{1}{M B_H}}\) where, \(I=\) Ml of magnet about the axis passing through its centre \(B_H=\) Earth's magnetic field…
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