TS EAMCET · Physics · Semiconductors
In the diode-based rectifier circuit given below, if \(V_s=V_m \sin \omega t\) and the diode is ideal, then the average value of \(V_L\) is
- A \(\frac{R_L}{\left(R_L+R_S\right)} \frac{V_m}{\pi}\)
- B \(R_L V_m \sin \omega t\)
- C \(\frac{R_L}{\left(R_L+R_S\right)} V_m\)
- D \(\frac{R_L}{\left(R_L+R_S\right)} V_m \sin \omega t\)
Answer & Solution
Correct Answer
(A) \(\frac{R_L}{\left(R_L+R_S\right)} \frac{V_m}{\pi}\)
Step-by-step Solution
Detailed explanation
Given, AC voItage, \(V_s=V_m \sin \omega t\) and \(V_m=\) maximum value of voltage In the given circuit diode will only conduct current in forward bias, so output across \(R_L\) will be Average voltage, \(V_{\mathrm{av}}=\frac{V_m}{\pi}\) average current…
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