TS EAMCET · Physics · Motion In One Dimension
Two buses \(A\) and \(B\) are moving in opposite direction. Now if the first bus \(A\) moves towards east with a speed of \(36 \mathrm{~km} / \mathrm{h}\) and bus \(B\) moves towards west with a speed of \(18 \mathrm{~km} / \mathrm{h}\), then the bus \(B\) appears to bus \(A\) as
- A moving with a speed of \(5 \mathrm{~m} / \mathrm{s}\) from east to west
- B moving with a speed of \(15 \mathrm{~m} / \mathrm{s}\) from west to east
- C moving with a speed of \(15 \mathrm{~m} / \mathrm{s}\) from east to west
- D moving with a speed of \(10 \mathrm{~m} / \mathrm{s}\) from east to west
Answer & Solution
Correct Answer
(C) moving with a speed of \(15 \mathrm{~m} / \mathrm{s}\) from east to west
Step-by-step Solution
Detailed explanation
The given situation is as shown in figure, Velocity of bus \(A, v_A=36 \mathrm{~km} / \mathrm{h}=36 \times \frac{5}{18}=10 \mathrm{~m} / \mathrm{s}\) Velocity of bus \(B, v_B=18 \mathrm{~km} / \mathrm{h}=18 \times \frac{5}{18}=5 \mathrm{~m} / \mathrm{s}\) Let the speed along…
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