TS EAMCET · Physics · Dual Nature of Matter
In a photoelectric effect experiment the cathode metal is exposed to light of wavelength \(600 \mathrm{~nm}\). The maximum kinetic energy of the ejected electron doubles when light of wavelength \(400 \mathrm{~nm}\) is used. The work function of the cathode metal is approximately. [Use \(h=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}, c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) ]
- A \(1.58 \mathrm{eV}\)
- B \(1.84 \mathrm{eV}\)
- C \(1.02 \mathrm{eV}\)
- D \(2.64 \mathrm{eV}\)
Answer & Solution
Correct Answer
(C) \(1.02 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
\(\frac{h c}{\lambda_2}=\frac{2}{2} m v^2+\phi=m v^2+\phi\)Wavelength of light, \(\lambda_1=600 \mathrm{~nm}\) If the work-function is \(\phi\) and the kinetic energy of electron is \(E_K=\frac{1}{2} m v^2\), then we can write,…
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