TS EAMCET · Physics · Ray Optics
Two convex lenses of focal lengths \(f_1\) and \(f_2\) form images with magnification \(m_1\) and \(m_2\), when used individually for an object kept at the same distance from the lenses. Then, \(f_1 / f_2\) is
- A \(\frac{m_1\left(1-m_1\right)}{m_2\left(1-m_2\right)}\)
- B \(\frac{m_1\left(1-m_2\right)}{m_2\left(1-m_1\right)}\)
- C \(\frac{m_2\left(1-m_1\right)}{m_1\left(1-m_2\right)}\)
- D \(\frac{m_2\left(1-m_2\right)}{m_1\left(1-m_1\right)}\)
Answer & Solution
Correct Answer
(B) \(\frac{m_1\left(1-m_2\right)}{m_2\left(1-m_1\right)}\)
Step-by-step Solution
Detailed explanation
The linear magnification of lens in terms of focal length \(f\) and \(u\). \[ m=\frac{f}{f+u} \] For first lens, \[ u_1=\left(\frac{1-m_1}{m_1}\right) f_1 \] For second lens, \[ u_2=\left(\frac{1-m_2}{m_2}\right) f_2 \] According to the question,…
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