TS EAMCET · Physics · Alternating Current
In the following circuit an \(\mathrm{AC}\) input \(V_i(t)=(20 \mathrm{mV}) \sin \left(10^5 t\right)\) is applied at the left end. The amplitude of the output voltage \(V_0\) at the right end across the capacitor will be

- A 14.14 mV
- B 10.55 mV
- C 20.2 mV
- D 25.55 mV
Answer & Solution
Correct Answer
(A) 14.14 mV
Step-by-step Solution
Detailed explanation
Given that, input AC voltage, Comparing Eqs. (i) and (ii), we get \(\omega=10^5 \mathrm{rad} / \mathrm{s}, V_{\max }=20 \mathrm{mV}=20 \times 10^{-3} \mathrm{~V}\) The \(V_i\) is distributed across \(R\) and \(C\). by \(V_R\) and \(V_C\), as phasor diagram. Reactance of…
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