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TS EAMCET · Physics · Motion In One Dimension

An object is thrown vertically upward with a speed of \(30 \mathrm{~m} / \mathrm{s}\). The velocity of the object half-a-second before it reaches the maximum height is

  1. A \(4.9 \mathrm{~m} / \mathrm{s}\)
  2. B \(9.8 \mathrm{~m} / \mathrm{s}\)
  3. C \(19.6 \mathrm{~m} / \mathrm{s}\)
  4. D \(25.1 \mathrm{~m} / \mathrm{s}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4.9 \mathrm{~m} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

According to the question, Velocity of an object half a second before maximum height = Velocity of an object half a second after maximum height (return journey) \[ =0+g t=0+9.8 \times \frac{1}{2}=4.9 \mathrm{~m} / \mathrm{s} \]
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