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TS EAMCET · Physics · Thermodynamics

Efficiency of a heat engine whose sink is at temperature of \(300 \mathrm{~K}\) is \(40 \%\). To increase the efficiency to \(60 \%\), keeping the sink temperature constant, the source temperature must be increased by

  1. A \(750 \mathrm{~K}\)
  2. B \(500 \mathrm{~K}\)
  3. C \(250 \mathrm{~K}\)
  4. D \(1000 \mathrm{~K}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(250 \mathrm{~K}\)

Step-by-step Solution

Detailed explanation

\[ \begin{array}{ll} \frac{T_2}{T_1}=1-\eta=1-\frac{40}{100}=\frac{3}{5} \\ \Rightarrow & T_1=\frac{5}{3} T_2 \\ \Rightarrow & T_1=\frac{5}{3} \times 300=500 \mathrm{~K} \end{array} \] New efficiency \(\eta^{\prime}=60 \%\)…
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